Question

Question 6 The following list shows the weights (in pounds) of 13-year old boys: 70 80 90 85 95 100 200 75 Which measure of central tendency is the best to represent this set of data? mean median mode mean, median, and mode Moving to another question will save this response.

Answer 1

(page1 we have weights (in pounds) of 13-year old boys 2.6 70,80, 90,85,95,100, 200,75 we compute mean of data, mean = sxi = 8 mean = 170+ 80 +90,85,95,100,200 +75) Imean = 99.375 Now, arranging data in ascending order, 70, 75, 80,85 ,90,95, 100,200 number of observations are 8 i.e. even number median = 85+90. 87.5 (85 and go are middle observations) Imedian = 87.5 and a 150, mode = most frequently observation There is no most likely observation. :. The given data is skewed, therefore median 9s the best to represent this set of data [ Questions we have, the time cin minutes ) it takes for each of the 7 calls received by a call center agent, 20,15,5 , 23,27,35,15 O mean = sum of all observations Total number of observations - 20 +15+5 +23+27 +35 +15 = 20 Imean = 20 minutes Now arrange the data in increasing order. 5, 15, 15,20,23,27,35 medion = middle value of the data = 20 minutes

page2 Imedian = 20 minutes) © mode = most frequently observation in the data mode = 15 minutes ..{15 is repeated 2 times? (2) Range = Uppet Value - lower value Upper value = 35 and lower value = 5 Range = 35-5 - 30 range = 30 minutes) @ variance = + ( xi-n7?), a mean ,n=7. Exi = (20+(153+ 559+(233+(273+(35)+(15)3= 3358 1. variance - +(3358 – 7X(20)2) = 558 = 79.7143 Tpopulation variance = 79.716