Question

The drawing shows three situations - A, B, and C - in which an observer and a source of electromagnetic waves are moving along the same line. In each case the source emits a wave that has a frequency of 4.57 x 1014 Hz. The arrows in each situation denote velocity vectors of the observer and source relative to the ground and have the magnitudes indicated (v or 2v), where the speed vis 1.6 X 10° m/s. Calculate the observed frequency in each of the three cases. A: B: f= C:f- Click if you would like to show Work for this question: Open Show Work

Answer 1

Given : 1 source of beter Electro Magnetic waves and an observer are moving. How, the frequency observed by observer will be different from orisinal frequency. This is called Doppler effect. 1. The observed frequency will be given by fla . Not to f. o Vous. fla Observed frequency ta actual frequency Vua velocity of sound wave. Vo a velocity of observer relative to source Vsa velocity of source. Vo ve will get fisns tvé oy ve depending on whether source foto is moving towards or away from the observer and vice-versa. Ai o a zvy fource. Observer foure towards source se. c towards moving is moving observer 2) V= tu. away from obsener source a) is moving veg 2 – 20

: f - wt af Vw -620) fol = vwth f Vw t2 Vw 2. 328* 3x10 m/s. ( since Be ware a light ware), va 1.6 x 106 mis (siven) to 4.57 x1004 42 Given) :.: the 3x1047 1.6X106 valy 3x108+ 2(1.6)X10C yout 1,6) 4.57 300+ 1.6 300+ 3.2 IFÀ = 4.54501074 Hz. گاه fource. observer is moving away from source > Vo: - source is moving away from observer >) : - 2V Vorut (trom ) pogla wao - rzus a very f i Votru

tola/ 3x1086-1.6x106) 1 X 4.57 x 10'4 32Lort 261.6 298.4 x 766 - 303.2 x 106 *4.57 %1014 VUL L v E obs Source toward's source observer is coming =) Vo = tu. source is moving towards source 2 V +V. from o - w tvo t (w ty) + Vw-V 3x108 + 1.66106 ) 4.57X104 HZ to = 3x108 1.68106 301.6 106 Xlo 6 7x 10' 1069 X4 296. 76.4 I fel a 4.619 8104 HZ