Question

1. Andrew and Jeff are attempting to determine if their GRE scores are high enough to get into the graduate schools they are interested in. DeCicco College has an average GRE score of 1550 with a standard deviation of 45. Jeff achieves a score of 1450 and Andrew a score of 1300.
   a. What is the probability of the score Jeff achieved occurring within those that are accepted to the university? (e.g. what is his percentile rank?)
   B. What is the probability of the score Andrew achieved occurring within those that are accepted to the university? (e.g. what is his percentile rank?)
   c. Is it probable that Jeff will be accepted based on his score?
   d. Is it probable that Andrew will be accepted based on his score?

2. Christine’s son is 2 months old and makes a visit to the pediatrician for a well-visit. The average height for a 2 month old in the US is 20 inches with a standard deviation of 2. Christine’s son is 22 inches.

1. • Determine his percentile rank.

   • What percentage of children fall between one standard deviation above and below
     the mean.

3. Adrian has a beagle named Sadie. Sadie has a healthy appetite and Adrian is concerned that she might be eating too much. Adrian weighs Sadie and finds she is 30 pounds. The national average is 25 pounds with a standard deviation of 3 pounds.
   a. Determine Sadie’s percentile rank.
   b. Should Adrian be very concerned about Sadie’s weight?

4. For a population with a mean of μ = 80 and a standard deviation of σ = 12, find the z- score corresponding to each of the following samples.
   a. M = 83 for a sample of n = 4 scores b. M = 83 for a sample of n = 16 scores c. M = 83 for a sample of n = 36 scores.

5. The population of IQ scores form a normal distribution with a μ = 100 and a standard deviation of σ = 10. What is the probability of obtaining a sample mean greater than M = 97,

1. • For a random sample of n = 9

   • For a random sample of n = 25 people

Answer 1

M=1550, o = 45 fell serve = 1450 w = 1300 Z-*- ~ N(011 @ PCJ < 1450) = P(Z < "450,1550) EP(Z < -2.22) = NORME DIST(-2.22) = 10.01327 PCA <1300) - PILE 1300-1510 0 45 = P(Z <-5.37) - NORMS DIST(-5.56) - 1 0.00001 ☺ e NO, blocese its puceutile pony = 1.32 No it is below en peelation