Question

(i.e. running the Euclidean algorithm backwards), find the general solution to each of the following:

  1. 312x+28y=\gcd\left(312,28\right)
  2. 250382 36972Y gcd (25038, 36972)
  3. 3219x + 6351y- gcd (3219,6351)
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Answer #1

(0) 3122《 + 2gg gcd (312,28) ged (23,312) 4 25038-2-1193 y +to Cd (25038 3692)2y 23니 -lo.XII to 119 3 y 11934-10(25038-2x1t

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