consider following reaction: 2 NO + Cl2⇌ 2 NOCl for which K= 6.25*10^4.
Calculate K for the following reaction 6 NOCl⇌ 6 NO + 3 Cl2
: 2 NO + Cl2⇌ 2 NOCl K = 6.25 x 104
if we reverse above reaction
2NOCl <--------------> 2NO + Cl2
Kc1 = 1 /Kc
Kc1 = 1 / 6.25 x104
Kc1 = 1.6 x 10-5
if we triple the reversed reaction
3NOCl <--------------> 3NO + 3Cl2
Kc11 = (Kc1)3
Kc11 = (1.6 x 10-5 )3
Kc11 = 4.1 x 10-15
consider following reaction: 2 NO + Cl2⇌ 2 NOCl for which K= 6.25*10^4. Calculate K for...
At 500.0 K, gaseous NOCl decomposed to NO and Cl2 according the
following reaction:
2NOCl(g) ⇌ 2NO(g) + Cl2(g)
If 1.00 mole of NOCl is placed in a 1.00 liter contained, and at
equilibrium, the
concentration is 0.91M, what is the equilibrium constant,
Kc?
4. At 500.0 K, gaseous NOCI decomposed to NO and Cl2 according the following reaction: 2NOCI(g) = 2NO(g) + Cl2(g) If 1.00 mole of NOCI is placed in a 1.00 liter contained, and at equilibrium, the...
Calculate the activation energy for the gas phase reaction: 2 NOCl(g) ® 2 NO(g) + Cl2(g) given the following data: T(K) rate constant (L mol-1s-1) 400 6.95 × 10-4 450 1.98 × 10-2 500 2.92 × 10-1 550 2.60 600 16.3
Consider the following reaction for which K 1.60 x 10 at some temperature 2 NOCl (g) ㄹ 2 NO (g) + Cl2(g) In a given experiment, 0.935 moles of NOCI(g) were placed in an otherwise empty 1.51 L vessel. Complete the following table by entering numerical values in the Initial row and values containing the variable "x" in the Change and Equilibrium rows. Define 2x as the amount (mol/L) of NOCI that reacts to reach equilbrium. Include signs in the...
Determine the value of K for the balanced reaction, 2 NOCl(g) ↔ N2(g) + O2(g) + Cl2(g) at 291 K given the following information, 2 N2(g) + 2 O2(g) ↔ 4 NO(g); K = 5.397×10-61 NO + 1/2 Cl2(g) ↔ NOCl(g); K = 2.432×104
Consider the reaction between NO and Cl2 to form NOCl: 2NO(g)+Cl2(g)⇌2NOCl(g) A reaction mixture at a certain temperature initially contains only [NO]= 0.65 M and [Cl2]= 0.64 M. After the reaction comes to equilibrium, the concentration of NOCl is 0.1 M. Find the value of the equilibrium constant (Kc) at this temperature.
Consider the reaction between NO and Cl2 to form NOCl: 2NO(g)+Cl2(g)⇌2NOCl(g) A reaction mixture at a certain temperature initially contains only [NO]= 0.66 M and [Cl2]= 0.51 M . After the reaction comes to equilibrium, the concentration of NOCl is 0.21 M . a)Find the value of the equilibrium constant (Kc) at this temperature.
2 NOCl(g) ⇄ 2 NO(g) + Cl2(g) Kp = 7.2× 10-6 1.50 atm of NOCl(g) is placed in a container and the system is allowed to reach equilibrium. Calculate the equilibrium pressure of Cl2(g) at equilibrium. 4.8 × 10-2 atm 8.5 × 10-3 atm 3.2 × 10-2 atm 2.4 × 10-2 atm 1.6 × 10-2 atm
The equilibrium constant, Kc, for the reaction 2 NOCl (g) ⇄ 2 NO (g) + Cl2 (g) is 2.4 x 10-7. What is the equilibrium constant for the reaction Cl2 (g) + 2 NO (g) ⇄ 2 NOCl
Consider the reaction between NO and Cl2 to form NOCl: 2NO(g)+Cl2(g)⇌2NOCl(g) A reaction mixture at a certain temperature initially contains only [NO]= 0.65 M and [Cl2]= 0.53. After the reaction comes to equilibrium, the concentration of NOCl is 0.25 M . ---Find the value of the equilibrium constant (Kc) at this temperature. Express your answer using two significant figures.
Consider the reaction between NO and Cl2 to form NOCl: 2NO(g)+Cl2(g)⇌2NOCl(g) A reaction mixture at a certain temperature initially contains only [NO]= 0.67 M and [Cl2]= 0.65. After the reaction comes to equilibrium, the concentration of NOCl is 0.15 M. Find the value of the equilibrium constant (Kc) at this temperature. Express your answer using two significant figures.