Question

please do this without the use of a program!

2. The enzyme activity of mannose-6-phosphate isomerase (MPI) was measured among three MPI genotypes in the amphipod crustacean Platorchestia platensis. Four males and four females were measured from genotype. Test for significant differences in enzyme activity due to sex (factor A) and genotype (factor B), and test for a significant interaction between sex and genotype. Use a 5% level of significance for each test. (12 points) (Warning! Carry lots of sig figs in your calculations!) Sex Enzyme Activity Genotype FF FS 4.3 2.5 SS 2.0 1.9 2.9 Female 4.0 Ni mimin 4.5 3.3 2.9 Male 3.9 4.4 4.2 3.0

Answer 1

Answer:

using excel>data >data ananlysis>two way anova

we have

Anova: Two-Factor With Replication
SUMMARY	FF	FS	SS	Total
Count	4	4	4	12
Sum	14.4	13.2	9.6	37.2
Average	3.6	3.3	2.4	3.1
Variance	0.333333	0.42	0.353333	0.585455
Count	4	4	4	12
Sum	18	14.4	12	44.4
Average	4.5	3.6	3	3.7
Variance	0.42	0.366667	0.44	0.749091
Total
Count	8	8	8
Sum	32.4	27.6	21.6
Average	4.05	3.45	2.7
Variance	0.554286	0.362857	0.442857
ANOVA
Source of Variation	SS	df	MS	F	P-value	F crit
Factor A	2.16	1	2.16	5.554286	0.029965	4.413873
Factor B	7.32	2	3.66	9.411429	0.001594	3.554557
Interaction	0.36	2	0.18	0.462857	0.636769	3.554557
Within	7	18	0.388889
Total	16.84	23

Since p value for Factor A is 0.03 <0.05 so we can say that there is a difference in enzyme activity due to sex

Since p value for Factor B is 0.002 <0.05 so we can say that there is no difference in enzyme activity due to genotype.

Since p value for interaction is 0.6368 >0.05 so we can say that there is no significant interaction between sex and genotype