Question

Problem (2) (Formerly presented as Problem 2) Option A) Knowing that at the instant shown the angular velocity of rod BE is 4.00 radians/s counterclockwise, please determine (a) the angular velocity of rod AD, (b) the velocity of collar D, ( the velocity of point A, and the location of the instantaneous center of (d) rotation of rod AD 192 30 360 mm

Answer 1

Rod A_D V_B = r_B/E w_BE = 0.192 times 4 = 0.768 m/s instantaneous Centre C is located by nothing that C_D is perpendicular to C V_D and C_B perpendicular to V_B r_B/C = 0.360 sin 30 = 0.180 ra w_A_D = V_B/r_B/C = 0.768/0.180 = 4.2667 rad/s w_A_D = 4.27 rad/sec Velocity of D r_D/C = 0.360 e_330 = 0.31177 m V_D = r_D/C w = 0.31177 times 4.2667 V_D = 1.330 m/s \r\n Velocity of A l_A_E = 0.240 w_330 = 0.20785 m l_CE = L_BE + L_BC = 0.600 sin 30 = 0.3 m tan_beta = 0.20785/0.3 = 34.7 l_CA = squareroot AE^2 + CE^2 = squareroot 0.20785^2 + 0.3^2 = 0.36497 m V_A = l_CA w_AD = 0.36497 times 4.2667 = 1.557 m/s.