(1 point) Find the angle of intersection of the plane 3x + 3y – 4z =...

Question

Question

(1 point) Find the angle of intersection of the plane 3x + 3y – 4z = –2 with the plane -5x – 5y – 2z = -4. Answer in radians:

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Answer 1

Answer #1

Given planes are: Plane I : 3x+3y-4z=-2 flame II: -56-54-2z = -4 Normal vector of plane1 n = <3,3-47 Normal rector of plane 2

Answer 2

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