Question 9 (20 points) Solve the initial value problem. - )- 4 3 X' -3 -2...
[-12 Points] DETAILS Solve the given initial-value problem. 1 -4 -6 X' 2 -3 X, X(0) = 1 1 -2 1 -( W NU -3 X(t) = Submit Answer [-12 Points] DETAILS Solve the given initial-value problem. x = $ =)x, x(0) = -(-3) X(t) =
18. + 14 points ZillDiffEQ9 8.2.031. Solve the given initial-value problem. 6 9 )X, X(0)=( x1 12/ 4 x(t) = Need Help? ReadTalk to a Tutor
QUESTION 3 After use Laplace Transform to transform the following initial value problem X" +x=e-t, x(0) = 1,x'(0) = 1, S-2 you should get X(s)= (write fraction as (S-2)/(5-4)(8+6) for -). Then, find (s-4)(8+6) x(t)= L-?{X(s)}= (write 5/6 by 5 -30 6' e^{-3t} by e and sin(2t) or cos(3t) by sin(2t) or cos(3t)).
Question 6 (30 points Solve the initial value problem. y"+8y + 16y = 0, y(0) = 1, y'(0) =1 y(t) = 5e-41 + te-4, Question 7 (30 points) Solve the following equation by undetermined coefficients. -67 5 C2e Question 9 (30 points) Solve for the general solution of the differential equation. Question 10 (10 points) Compute using the table of Laplace Transforms. (s-2) (r-2) (s+2 6 (s+2)
Question 9: Find the solution of the following initial- value problem, d x x² + xt subject to the initial condition dt 12 X = 1 at t = 1
Problem 3: Solve the initial value problem and write your solution as a piecewise func- tion: y () y(0) A,y(0) with cos(2t), cos (2t) +cos (2t - 12), t2 6 f(t)
Problem 3: Solve the following initial value / Neumann problem by separation of variables: (8 points) U4 - 9uzz = 0, (t, x) € Rx (0,2), u(0, 2) = cos? (17), 4(0, 1) = [1 $("))", uz(t,0) = un(t, 2) = 0. - COS
Solve the following initial value problem 1 2 3 4 01 63 0 012 x +e' 0001 o x(0)0 Solve the following initial value problem 1 2 3 4 01 63 0 012 x +e' 0001 o x(0)0
QUESTION 2 use to the following initial value problem (write fraction as (s- After Laplace Transform transform x" + 2x' +x=3, x(O)=0,x'(0)=1, you should get X(s)= S-2 2)/(S-4)(s+6) for (s-4)(8+6) -). Then, find x(t)= L-(x(s))= 5 -3t (write 5/6 by 6' e^{-3t} by e and sin(2t) or cos(3t) by sin(2t) or cos(3t)).
(write After use Laplace Transform to transform the following initial value problem x" + 2x' +x=3, x(0)=0,x'(0)=1, you should get X(s)= S-2 fraction as (S-2)/(S-4)(8+6) for -). Then, find x(t) = £-2(x(s)= (s-4)(3+6) (write 5/6 by 5 -3t 6' , e^{-3t} by e and sin(2t) or cos(3t) by sin(2t) or cos(3t)).