on the 50 foot side of a house, a 3 sided fence is made out of 44 feet of fencing, with 2 of the three sides being the same length.
What is the maximum area, in square feet for the garden if all of the 44 feet of fencing is used
fencing = 44 feet
let length = l
width = w
2w + l = 44
l = 44- 2w
area = length * width
= w( 44 - 2w )
= 44w - 2w^2
maximum area occurs at
w = - b/2a
w = - 44/ 2(-2)
w = 11
l = 44 - 2(11) = 22
area = 22(11)
maximum area = 242 square feet |
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