Question

I dont have excel please help! It's asking to calculate the acceleration, then calculate the m_hg, then graph them, and report the slope. The slope is the mass of Bob.

A group of students, performing the same "Uniform Circular Motion" experiment that you performed in lab, obtained the following results. r(m) mn (kg) t(s) 0.1825 0.06625 172.57 0.2430 0.0965 169.38| 0.2610 0.1055 71.27 0.2980 0.124 170.28 0.3425 0.14625 |71.91 For this table, r is the distance from the center of rotation to the radius indicator (i.e., the post that marks the position of the center of the bob during rotation), mn is the total hanging mass (including the hanger), and t is the time required for 50 complete rotations. Use Excel to construct a spreadsheet that show the following. (You will not submit this spreadsheet. However, the results will be needed later in this problem.) (i) the above data (ii) all calculations needed to compute the acceleration, a, for each trial _ HINT (iii) a graph of mng vs ar HINT (iv) Use the trendline option to draw the best fit line and determine its slope. — HINT (b) Report this value below. mass of the bob =

Answer 1

@ for circular motion, acceleration ac = Again, &- 200 yo 2p2 T2 - 412 72 " T= 72.57 = 1.4514 see. a = 472 x 0.1825 (104514) 2 = 3.4201 myse T= 69.38 o 50 = 1.3876 see. ac = 417² x 0.2430 (103876)2 = 4.9773 nisa F1: 27 - 50 = 104254 see a = 402 x 0.2610 5.0662 m2 (1942542 T = 70.28 50 = 1.4056 see a = 4² x 0.2980 1.4056 = 5.9485 m2 & T = Holl = 1.4382 sec SO a = 402 x 0.3425 (10438222 = 6.530 4 miz

ae (2182) • 420) mag (N) О»ob625 90% - О,6492 . 04 9451 1.o339 ч 927 3 • 2152 5.ob62 Б• 9 485 6. 5304 1°4 33 slope 18 x 0.01 19 x б065 с. б. 2406 vа. 2, MG gg of boy - о, 24а, 19 ,

0.65 2.42 4.04 4. 66 5.29