Consider the following figure. o G Given: mZDOE78º and mZEOG - 88° in Oo EF is...

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Given poc - 4e & E06 = 88, EF is diameter ay be measure of an are is equal to the angle which it makes at the center of the

Now, consider AEOG: LOGE = LGEO (since oG & OE are radius) LEOG + LOGE + LGIEO = 180° 2 LOGE LEOG = 180° 2 LOGE = 180° - 88

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