Question

Need answer as soon as possible, don't need explanation

Assume we have a physical implementation of the MARIE architecture. If a software trap occurs, which of the following statements would be true? Note that you may select more than one answers but incorrect answers will reduce the overall score for the question (your grade will never be less than 0) Select one or more: a. The current value of the AC does not need to be saved for later use since it will just be recalculated when the program restarts b. The Interrupt Service Routine can not use any of the registers being used by the current application. c. Without interrupts, the operating system would not be able to regain control of the CPU once a user application started to execute. d. An Interrupt Service routine can not run if an application is currently using the CPU e. The value of the PC register for the current program must be saved so that it can be used after the ISR is executed

Answer 1

Answer:-----------
c. Without interrupts, the operating system would not be able to regain control of the CPU once a user application started to execute.
e. The value of the PC register for the current program must be saved so that it can be used after the ISR is executed