Question

Determine delta H(vap) for a molecule with a Vapor pressure of 25.2 torr at 273 K and 56.2 torr at 295 K.

Answer 1

Delta H_vap for a molecule vapor pressure of 25.2 torr at 273 k 56.2 torr at 295 k Using the Clausius clay person Equation ln (P_2/P_1) = Delta x/R (1/T_1 - 1/T_2) with the values P_1 = 25.2 torr P_2 = 56.2 torr T_1 = 273 k T_2 = 295 K ln(56.2/25.2) = Delta x/8.314 (1/273 - 1/298) we solve & get Delta H = 24411.01 J/mol = 24.41 kJ/mol.