Question

i have solve it several time but the answer is wrong , they are both one question

At Center Hospital there is some concern about the high turnover of nurses. A survey was done to determine wlong (in months) nurses had been in their current positions The responses (in mouths) of 20 murses were as follows 5.8, 10, 11, 11, 14, 15, 17, 23.26.26, 28, 29, 30, 31, 32, 34, 39, 39, 45 (a) Which percentile is the value 45? (Round to the nearest whole value above) 45 is the th percentile (6) Find the 8th percentile on the data Locator Sth percentile (c) Find the Q. value on the data Locator Q. = 125 (d) Find the Qal the data Locator Q. - 315 (e) Find the value on the data 26

Answer 1

Data:

5, 8, 10, 11, 11, 14, 15, 17, 23, 26, 26, 28, 29, 30, 31, 32, 34, 39, 39, 45

a) 45 is the 100th percentile.

location of 45 is 20, hencence percentile = (20/20)*100 % = 100th percentile.

b) 8th percentile of the data,

Locator = (21*8)/100 = 1.68 th item.

8th Percentile = 1st item + 0.68 (2nd - 1st) item

= 5 + 0.68 *(8-5) = 7.04 (ans)

c) Q1 value,

Locator = (21/4) = 5.25 th item

Q1 = 5th item + 0.25 (6th -5th)

= 11 + 0.25* (14-11) = 11.75

d) Q3 value,

Locator = (3*21)/4 = 15.75 th item

Q3 = 15 th item + 0.75 (16th - 15th)

= 31 + 0.75(32-31) = 31.75

e) Q2 = Average of 10th and 11 th item

= (26+26)/2 = 26

f) IQR = Q3 - Q1 = 31.75 - 11.75 = 20

g) Upper limit = Q3 + 1.5 IQR

= 31.75 + 1.5*20 = 61.75

Lower limit = Q1 - 1.5 IQR

= 11.75 - 1.5*20 = -18.25

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