Question

Calculate the work necessary to isothermally perform steady compression of 2 moles of an ideal gas from 1 bar to 10 bar and 311K in a piston. An isothermal process is one at constant  Temperature. The steady compression of the gas should be performed such that the pressure of the system is always practically equal to the external pressure on the system. This is referred to as reversible compression.

Answer 1

Solution Pressure before compression Pi : 1 box - P. = LookPa Cgiven) Pressure after compression P2 = 10 bar = P2 = 10ookPa isothermal process .. Ti - Tz = 311 ks P 2 - isothermal process For work donc PV, en (2) V volume before after isothermal Process Compressions Compresion V₂ - Volume 3. Εογ idcol gas PV = nRT R> universal gas constant n = 2 moles n number of Povi = nRT, moles nkz Pi

R = 8.314 kJ/kc mol k Vi = 2*8.314 X 311 3 51.713 m 100 We Pivo en/ve ences) Piv. = P2 V2 (isothermal proces Pi P2 Pov, en » w- () W = 100x 51.713 « l» (Yoo W=-11907.358 kJ Mo (-ve system) means work done W= 11907.358 kJ the isothermol The work done for Compression process 11907.358 kJ