Question

please answer questions 1-4

Divide using long division. (Show all work!) x2-x+3 6x2 +7x+5 3x-1 X+1 z! 15y3+y2–217 5y-3 2x3-29x+ x+4

Answer 1

Write the problem in Write the problem in the format: x +1 ) x2 –& +3 Divide the leading term of the dividend by the leading term of the divisor in sucessive steps Hints -2 ) x2 +2 | x +1 +3 x2 - + - 2x +3 x (x + 1) = x2 + x - 2+ = -2 -22 -2 -2(x + 1) = -2x – 2 Therefore, 02 – +3 - x + 1 = X – 2 + - 2+ 1

2. Write the problem in the format 3x – 1 6x2 +7x +5 Divide the leading term of the dividend by the leading term of the divisor in sucessive steps Hints 2x +3 6x2 +7 3x – 1 +5 2x 6x2 -22 9x +5 2. (3x – 1) = 6x2 – 2x g = 3 9x 3 (3x – 1) = 9x – 3 -3 8 6x2 + 7x + 5 Therefore, -= 2x + 3+ 3x – 1 Therefore, 6a24 29 + 5 = 2x +3+ 3x – 1

3. Write the problem in the format (missed terms are written with zero coefficients 5y – 3 ) 1543 +y–217 +0 Divide the leading term of the dividend by the leading term of the divisor in sucessive steps Hints 3y2 +24 -3 ) 15y3 +y2 –217 +0 5y – 3 1543 -9y2 1092 -214 +0 3y² (5y – 3) = 15y3 – 9y2 hout = 2y 2ly +0 10y2 -6y - 154 2 y(5y – 3) = 10y2 – 6y - 15y = -3 +0 54 = -15y +9 -3(5y – 3) = -15y+9 -9 15y3 + y2 – 21y = 3y2 + 2y – 3+ 54 - 3 -9 5y - 3
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4. Write the problem in the format (missed terms are written with zero coefficients) 2+4 203 +0x2–292 +0 Divide the leading term of the dividend by the leading term of the divisor in sucessive steps Hints x+4 22 -8x +3 223 +022 –291 +0 27.5 = 222 2.03 +872 232 (x + 4) = 2.03 + 8x2 =8z? = -82 -822 -292 +0 –8x2 8 0 –32. 32 3 (r + 4) = -8x2 – 32x = 3 +0 — 3x +12 -12 3(2x + 4) = 3x + 12 Therefore, 2.23 – 292 € = 2.e– 8x +3+ * +4 -12 3 +4