A 95.0-Ω resistor has a constant current of 3.50 A passing through it. What is the...
A 95.0-Ω resistor has a constant current of 3.50 A passing through it. What is the rate at which heat is being released from this resistor (in Watts)?
Homework Answers
Heat released =i^2*R*t
Rate of change of heat = heat released /time
So from the above equation
Rate of change of heat = i^2*r
= 3.5*3.5*95
=1163.75 watt
Add Answer to:
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