The elastic potential energy stored in the spring is converted
to gravitational potential energy
(1/2)kx^2 = m g h
The maximum height reached is
h = kx^2 / 2mg
= (350)(0.08)^2 / 2(0.35)(9.8)
= 0.3265m
=32cm
100642 C Exercise 5.58 Part A A vertical spring with a force constant of 350 N/m...
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