Question

C++ code do while loop issue. The code I posted works but when it prompts the user if they want to try against with another sentence, it only takes the Y and goes straight into another loop, without letting me enter a new sentence. I need it to be able to take the Y response from a user and then let me enter another sentence.
do
{
cout<<"Enter a sentence:"; //user input sentence
cin.getline(str,80);
int wordsCount = 0;

for (int i=0;str[i] !='\0'; i++) //making space for null
{
if (str[i] == ' ')//checking for space
{
wordsCount++;
}
}
my print out code.....
  

//ask user to enter another sentence
cout << "Try Again? (Y/N)\n";
cin>>input;

}while ((input == 'y') ||( input == 'Y'));
return 0;

Answer 1

Just add one line that is cin.ignore(); this line eat the \n

we take value for input (y/n) and press enter "\n" is stored in the str next time so we are unable take next time sentence

  

#include<string.h>
#include <iostream>

using namespace std;

int main()
{
char str[80],input;

do
{
cout<<"Enter a sentence:"; //user input sentence
cin.getline(str,80);

int wordsCount = 0;

for (int i=0;str[i] !='\0'; i++) //making space for null
{
if (str[i] == ' ')//checking for space
{
wordsCount++;
}
}
//my print out code.....
  

//ask user to enter another sentence
cout << "Try Again? (Y/N)\n";
cin>>input;
cin.ignore(); //eat the \n value  

// if not used cin.ignore(). \n value is stored in str. so you unable type next time sentence

}while ((input == 'y') ||( input == 'Y'));
return 0;

}

Screenshot of the program :

7 int main() 9 o 1- 2 3 char str[80], input; do { cout<<"Enter a sentence:"; //user input sentence cin.getline(str, 80); 5 int wordsCount = 0; for (int i=0;str[i] !='\0'; i++) //making space for null, 7 _8- 9 if (str[i] == ' //checking for space, 21 wordsCount++; 12 3 } 4 //my print out code..... 18 //ask user to enter another sentence cout << "Try Again? (Y/N)\n"; cin>>input; cin.ignore(); 2 3 }while ((input == 'y') ||( input == 'Y')); return 0; 5 }

out put:

Enter a sentence:cplus plus is good programming language Try Again? (Y/N) Enter a sentence:but i like c language Try Again? (Y/N) Enter a sentence: Python is fun Try Again? (Y/N) ... Program finished with exit code o Press ENTER to exit console. I