Question

please help with this problem!

Situation: A 0.80-meter spring is set on top of a table. The tabletop is 1.0 meters in length. The table is pushed up against a wall and one end of the spring is attached to the wall. A woodblock of mass 0.1kg is placed at the other end of the free spring. The woodblock is pushed against the spring causing the spring to compress. When held in place, the spring's compressed length is now 0.30 meters. a. How much Work did the compressed Spring do on the woodblock? (hint: the spring only does work on the woodblock as long as there was contact.) So go back to tabletop and visualize the compressed spring and woodblock right before the spring was released. Then once released, the spring and woodblock stayed together, but at some point, the spring and woodblock lost contact. For what distance did spring and woodblock maintain contact? (And Work = F xd) b. Right before the compressed spring with a block was released, what was the stored Potential Energy? Trick question. If you are thinking PE = mgh, then you are thinking wrong. This was a horizontal spring, there was no height for the spring itself. So think, how do you get to the Potential energy?

SPRING CONSTANT, known as "k", IS 18 N/m

Answer 1

0.8m 0.3m பணன் cal when compreneal spring is release it will mountain the contact with the wooden block until it achieves its natural pontion, since the wooden block is not attached to the spring, so after reaching to its natural langth the spring will stop expanding and will come to stop but the block clue to its martia will continue to move and hence will lose contact with the spring, so the work done by spring on s FR 0.8 eds = kx dx = 07 worl= TE 10 10.3 2 - (0.36-0,3°) - 12 [0.55) I work = 4.951J since force inel displacement are! in same direction so we get I positive work- B) we know that stored potential energy in a spring is same as work done in compressing the spring to the given point. so compressing spring to 0.3m will store the same energy as work done to compress the spring. PE = from pele -KIEL 2-18|634-0.3°) 0.8 2 = -4.955 as So stored energy will be same in magnitucle the work clone es pot energy storel = 4.955/ CamScanner