Exam ans fast 2. (a) in Figure what value must R have if the current in...

Question

Question

Exam ans fast

Answer 1

Answer #1

a)

equivalent resistance

R_eq=2+2+R=4+R

Net Voltage

E_net =3-1=2 V

Current in the circuit is

I=E_net/R_eq

=>R_eq=E_net/I =2/(5*10^-3) =400 ohms

4+R=400

R=396 ohms

b)

Power dissipated in resistor R is

P_R=I²R=(5*10^-3)²*396

P_R=9.9*10^-3Watts

Answer 2

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