Homework Answers
Ans 1 :
a)
Let us consider 1 mol of compound HBr
So mass of H will be = 1 g
mass of Br will be = 80 g
total mass of one mole = 1 g + 80 g = 81 g
Mass fraction of H = ( mass of H / total mass)
= ( 1 g / 81 g )
= 0.012
mass fraction of Br = 1 - mass fraction of H
= 0.988
b)
1 mol of HBr has one mole H and one mole Br
total mole of both H and Br = 1 + 1 = 2
mol fraction Br = ( mol Br / total mole)
= 1 / 2
= 0.5
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