Question

in java

Define a class named ComparableNames thats extends Person and implements comparable

Define a class named ComparableNames that extends Person (defined below) and implements Comparable. Override the compare To method to compare the person on the basis of name. Write a test class to find the order of two ComparableNames. class Person String name; Person00 Person(String n) name=n: Hint: in class ComparableName, you only need a constructor with arg to initialize the data filed defined in the super class a method that override method compare to defined in interface Comparable. In Test class, create two objects of class ComparableName with two names and use method compare To: if both names are the same, print "both names are the same'. otherwise, print them in order.

Answer 1

Given below is the code for the question. Please do rate the answer if it helped. Thank you.

Person.java
-----
class Person
{
   String name;
  
   Person(){}
   Person(String n)
   {
       name = n;
   }
}

ComparableNames.java
---------
class ComparableNames extends Person implements Comparable<Person>
{
   public ComparableNames(String n){
       super(n);
   }
  
   public int compareTo(Person p){
       return name.compareTo(p.name);
   }
}

TestComparableNames.java
-----------
public class TestComparableNames
{
   public static void main(String[] args){
       ComparableNames n1 = new ComparableNames("John");
       ComparableNames n2 = new ComparableNames("Bob");
       if(n1.compareTo(n2) == 0)
           System.out.println("both names are same");
       if(n1.compareTo(n2) < 0){
           System.out.println(n1.name);
           System.out.println(n2.name);
       }
       else if(n1.compareTo(n2) > 0){
           System.out.println(n2.name);
           System.out.println(n1.name);

       }
   }
}