Question

CruzlD: @ucsc.odu Arithmetic and Logical Operations 19. Which of these 8-bit two's complement computations has carry out but no overflow? Select two answers: 1 1 011001 10 0 111 1 110 O A. averflas 1IIOOIOO O B. 1 0000000 has 11 1 1 111 1 co has c.o 1110i no dverfle + 0100 1101 1 1 01 011 O D. overluw + 0101 1 1 0 1 E 1 1 10 1 0 + 11 1 1 1000 20. Using 4-bit two's complement arithmetic, which of the following additions will result in overflow? 3) 1111 2) 0011 1) 1100 +0111 +0111 +1100 O A. 1 and 3 3 only C. 1 only I and 2 B. C O E D. 2 only 21. Perform the following 5-bit two's complement addition. 1 0011 + 0 01 1 1 What is the answer in 5-bit sign magnitude? O A. 10110 O B. 01010 O C. 11011 O D. 00110 11010 O E Page 6 of 9 O000

Answer 1

19) 8-bit a's complement format: [sign | Data , I bit abits ar sig n = 6=> positive sign 21 =) negative. P . 11 UCI c R O 110 oilo s positive 01111 110 positive I110 0 10o – negative (Adding of 2 positive give meest ... Overflow oc cwritte positive), ) B) 1000 0000 ooo 0 0 0 0 du 1111 !! i t Novi 100l - negative ID . negative positive.. ( result must negative) s Discard carry Tover flow occurs 1-10 - hot son ITTO 1011 negative O100 1101 → positive JOOP! 1000 > positive RSD Discard carry () on No ovef loco) option - E correct ( positivat negative = positive true) OLTO 1011 0 101 1101 o 100 1000 =) No Carry, so not a valid option,

E) TiiO ILLO - negative Ili II000 - negative UTITOOIIO i negative L) Discard Carry .. No overflow occar.. Coption-E) . Coption C,E correct 20) 4. bit .d's complement format sigo Daba T sign=1 negative Ibit 3bits Sign=0 positive. D1100.-). negative 1100 - negative D1000 - negative. No overflow) 2 0 0 1 -) positive O LI -Positive 7010 negative occia) Lover flow negative 3). Tils y positive 011.2 jollo y positive Discar (no over flow) Option. E)

5-bit two's complement addition T0 0 1 00111 TOIO 5-bit format sign | Data , 1 bit 4 bits 1 11010 e signal to get original number perform a's complement i's complement: 0 0 16, 1 cm Pince 00110 convert to decimal :-(182"+1x2 =-(2+4)* 6 = 4+2=81lo. 6 10 negative number so sign=1 Magnitude 20110. 5 - bit sign magnitude format Lionel (Option - A correct) sign Magnitude.