Please see below help would be appreciated, thanks in advance!
a) v^2 = v0^2 + 2 a x
5^2 = 0^2 + 2*a*2
25 = 4 a
a = 6.25 m/s^2
b) F = ma = 2*6.25 = 12.5 N
c)
now F - friction = m a
friction = u m g
F = um g + ma = 0.5*2*9.81+12.5=22.31 N
d)same as part a
a = 6.25 m/s^2
e) now F - mg sin theta = m a
F = mg sin theta + m a = 2*9.81*sin(30 degrees) +12.5= 22.31 N
f) so sum forces perp to slope
N - m g cos theta = 0
N = mg cos theta
so friction = u N = u m g cos theta
F - m g sin theta - friction = ma
F = 2*9.81*sin(30 degrees) +12.5 + 0.5*2*9.81*cos(30 degrees)= 30.8 n
g)
now when you sum perp to slope
N - mg cos theta - F sin theta = 0
N = m g cos theta + F sin theta
so now sum with slope
F cos theta - m g sin theta - u ( mg cos theta + F sin theta) = ma
F*cos(30 degrees) - 2*9.81*sin(30 degrees) - 0.5*(2*9.81*cos(30
degrees) +F*sin(30 degrees) ) = 2*6.25
F=50 N
a)
V^2=U^2+2aS
25=0+2a*2
a=6.25m/s2
b)
V^2=U^2+2aS
25=0+2a*2
a=6.25m/
Fnet=F=ma=2*6.25=12.5N
c)
V^2=U^2+2aS
25=0+2a*2
a=6.25m/s2
Fnet=ma=2*6.25=12.5N
F-f=Fnet
F=Fnet+f=12.5+umg=12.5+0.5*2*9.81=22.31N
d)
V^2=U^2+2aS
25=0+2a*2
a=6.25m/s2
e)
V^2=U^2+2aS
25=0+2a*2
a=6.25m/s2
Fnet=ma=2*6.25=12.5N
F-mgsin(theta)=Fnet
F=Fnet+mgsin(theta)=12.5+2*9.81*sin(30)=12.5+2*9.81*0.5=22.31N
f)
V^2=U^2+2aS
25=0+2a*2
a=6.25m/s2
F-mgsin(theta)-f=Fnet
F=Fnet+mgsin(theta)+f=Fnet+mgsin(theta)+umgcos(theta)=12.5+2*9.81*sin(30)+0.5*2*9.81*cos(30)=
=12.5+2*9.81*0.5+0.5*2*9.81*0.866=30.8057N
g)
V^2=U^2+2aS
25=0+2a*2
a=6.25m/s2
Fnet=ma=2*6.25=12.5N
Fcos30-mgsin(theta)-f=Fnet
Fcos(30)=Fnet+mgsin(theta)+f=Fnet+mgsin(theta)+u(mgcos(theta)+Fsin(30))
0.866F=12.5+2*9.81*sin(30)+0.5(2*9.81*0.866+0.5F)
0.366F=12.5+2*9.81*0.5+0.5*2*9.81*0.866=30.8057N
F=30.8057/0.366=84.1686N
Please see below help would be appreciated, thanks in advance! What acceleration is required to accelerate...
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