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(10 points) Consider the function f()= Vz +1. Let Th be the nth degree Taylor approximation...
(1 point) Consider the function f(x) = Vx + 1. Let Tn be the nth degree Taylor approximation of f(10) about x = 8. Find: T = T2 = Use 3 decimal places in your answer, but make sure you carry all decimals when performing calculations T, is an (over/under) estimate of f(10). If R2 is the remainder given by the Lagrange Remainder Formula: |R2| =
(1 point) Consider the function f(x) = xin(x). Let T, be the degree Taylor approximation of f(2) about x = 1. Find: T = T = Use 3 decimal places in your answer, but make sure you carry all decimals when performing calculations T3 is an (over/under) estimate of f(2). If R3 is the remainder given by the Lagrange Remainder Formula: |R3|
CALCULUS Consider the function f : R2 → R, defined by ï. Exam 2018 (a) Find the first-order Taylor approximation at the point Xo-(1, -2) and use it to find an approximate value for f(1.1, -2.1 (b) Calculate the Hessian ã (x-xo)' (H/(%)) (x-xo) at xo (1,-2) (c) Find the second-order Taylor approximation at Xo (1,-2) and use it to find an approximate value for f(1.1, -2.1) Use the calculator to compute the exact value of the function f(1.1,-2.1) 2....
2. Let 6 marks (a) Find f(x),f"(x), and f"(x). (b) Find the second order Taylor expansion of f at 1, namely f(r) = ao + ala-1 ) + a2(z-1)2 + R2(x), where Ra is the remainder. You should find ao, a, a2, and R(p). 8 marks that the error in this estimation (i.e., R2(0.9)1) is at most 10-3. 6 marks (c) Use the Taylor expansion found above to estimate the value of f(0.9). Show Find f(x), f"(), and f" (b)...
Consider the following function. /(x)=x-5, a= 1, n= 2, 0.8SXS 1.2 (a) Approximate f by a Taylor polynomial with degree n at the number a T2(x) = (b) Use Taylor's Inequality to estimate the accuracy of the approximation x) ~ Tn(x) when x lies in the given interval. (Round your answer to six decimal places.) (c) Check your result in part (b) by graphing Rn(x) 0.6 0.4 0.2 0.6 0.4 0.2 0.9 0.9 1.2 -0.2 -0.4 -0.6 -0.2 -0.4 -0.6...
Consider the function f (x) = ln (1 + x). (a) Enter the degree-n term in the Taylor Series around x = 0. (b) Enter the error term En (z) which will also be a function of x and n. (c) Find an upper bound for the absolute value of the error term when x > 0. It may help to remember that z is between x and 0. (d) Use this formula to find how many terms are needed...
question b please Consider the following function f(x) -x6/7, a-1, n-3, 0.7 sx 1.3 (a) Approximate f by a Taylor polynomial with degree n at the number a 343 (b) Use Taylor's Inequality to estimate the accuracy of the approximation f(x) ,(x) when x lies in the given interval. (Round your answer to eight decimal places.) IR3(x)0.00031049 (c) Check your result in part (b) by graphing Rn(x)l 2 1.3 0.00015 0 0.9 1.0 11 -0.00005 0.00010 -0.00010 0.00005 0.00015 0.8...
Consider the function f(x) := v/x= x1/2. 6. (a) Give the Taylor polynomial P(x) of degree 5 about a1 of this function (b) Give the nested representation of the polynomial Qs()Ps((t)) where t -1 ((t)+1). (c) Using the nested multiplication method (also called Horner's algorithm), compute the approximation Ps (1.2) to V (give at least 12 significant digits of P(1.2)) (d) Without using the exact value of 12, compute by hand an upper bound on the absolute error V1.2 A(1.21...
10. Trapezoidal Rule is used to approximate the integral f(a) dx using 1- (yo +2y1 + 2y2 + x-na b-a + 2yn-1 +%),where Use this approximation technique to estimate the area under the curve y = sinx over。 a. π with n 4 partitions. x A 0 B: @ Δy B-A b. The error formula for the trapezoidal rule is RSL (12ba)1 where cischosen on the interval [a, b] to maximize lf" (c)l. Use this to compute the error bound...
- Question 2 3 points Consider the function f (x) = ln (1+2). (a) Enter the degree-n term in the Taylor Series around x = 0. ((-1)^(n-1)*x^n)/n (b) Enter the error term En (2) which will also be a function of x and n. ((-1)^n*x^(n+1))/((n+1)*(1+z)^(n+1) (c) Find an upper bound for the absolute value of the error term when x > 0. It may help to remember that z is between x and 0. x^(n+1)/(n+1) 90 (d) Use this formula...