Question

6. (15 pts) A website tracks the mumber of users that follow a link provided by an advertiser. On a randomly selected day, 22 out of 542 visitors clicked on the ad link. After the advertising group modified their ad, it was observed on a different randomly selected day that 64 out of 601 visitors followed the link provided by the ad. Were the advertisers successful in attracting more customers?

Answer 1

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After modification Before modification in=542 x = 22 P = 22 542 i p= 0.041 n₂=601 X₂ =64 P= 64 601 - 0.106 claim: has were advertisement modification an impact on customers This is 2-sample difference for propostyor test of proportion WLT , broo proportions are well described binomial disth, but since n is lange , we can alcume Normality Null hypothesis ; Ho : P₂ - P = 0 or P₂ =P Alternative hyppo ; Ha p-p,20 or l>e, assurning d= 0.05 - level of significance = std. enor (S.E.) is given by J = p § + 22 Where is estimated in two overall Doon. proportion

nipi + 2 p2 - n+12 = (542) (0.04) + (601) C0.106) 542+601 P = - 0.075 1-0075 4. Q = 0.925 Tips fpå ( 1 - 2 - 1 (0.075)(0-125). (to dow) 0.0156 acceptance Abiye Reg. From to 2, table, coneepondig a critical z -value is 1.645 z - +1.645 = Test statistic is given by = 4.22 0.066 - 0 0.0156

& TS falls in rejection region, in We reject null. Conclusion: Advertisers successfully attracted more customers.