Question

5.3 The portable engine hoist shown in the figure weighs 275 lb. This weight acts as if concentrated at the machine's center of gravity (c.g.). A chain at E is used to support the 640-lb load. (a) Find the support forces provided at wheels A and F.

Answer 1

Solution:- (5.3) The free body diagram of the given figurie. 26" - E 201 37.60 27515 A 184 40 Given weight The load 25016 at support Ers, 640 16 ca) Calculation of supported wheels at A and F Reaction at A is, RA Reaction at F IS, RE By Considering me equation at 91 whical digeelion weget, Ratry =640+275 RAIRE = 915 16 0 Scanned with CamScanner

By taking moments about A, we get - (275x18 ) +1RfX58) -(640x48) = 0 Re (225x18 ) +(640x48) 58 RE = 61516 By subestetiborg The above valve mu equation I wenget. RA=915-615 RA= 300 Ib Therefore, The reactions at A and F is FRA= 300 Ib/ RE=61516 (6) Calculation of length of CDE extended. 37.6 640 16 22516 A 181 40" Scanned with CamScanner

let x = leugn of CDE extended for its present ♡ position dete ne host lips ( 7. In This case, RAFO More file, by taking the moments at A, we get (915x58 )-(245x18 ) -(640xx) = 0 2- (95x58 )-(245x18 ) 640 x = 53070-4950 640 X = 48120 640 = 75.189 There-tone, additionally CDE to be extended forowy its corrent position is = 75-18-48 = 27.18 on Scanned with CamScanner