Question

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Consider the following circuit: At what rate does the battery deliver energy to the circuit? Find the current through the 40 OHM resistor. Determine the potential difference between points a and b. At which of these two points is the potential higher? Find the energy dissipated by the 100 ohm resistor in 10 s. Given that the 100 ohm resistor is a solid cylinder that is 4 cm long, composed of a material whose resistivity is 0.45 ohm middot m, determine its radius. Consider the following circuit: What is the current through each resistor? What is the potential difference across each resistor? What is the equivalent resistance of the circuit?

Answer 1

120 - 30 i_1 = 40 i_2 = 120 i_3 i_1 = i_2 + i_3 120 = 70 i_2 + 30 i_3 120 = 30 i_2 + 150 i_3. I_2 = 1.5 i_3 = 0.5 i_1 = 2 A a) P = i_1 times v = 2 times 120 = 240 j/s. b) i_2 = 1.5 A c) v_ab = 40 times 1.5 = 60 v d) i^2_3 times 10 = 0.25 times 100 times 10 = 250 j e) R = rho l/A r = squareroot 0.45 times 4 times 10^- 2/ pi times 100 = 7.57mm 2) a) i_20 = i_40 = i_60 = i_60 = 0.5 A i_10 = 0.5 + 0.5 + 0.5 = 1.5 A b)V_10 = 10 times 1.5 = 15 v V_60 = 0.5 times 60 = 30 v V_60 = 0.5 times 60 = 30 v V_20 = 0.5 times 20 = 10 v V_40 0.5 times 40 = 20 v c) Req = 10 + 60/3 = 30 R.