ZuoTi.Pro
Question
Problem 3.16 ;;
SG= 1.595
Please clear hind writing
3.15 A partitioned tank as shown contains water and mercury. What is the gage pressure in the air trapped in the left chamber? What pres- sure would the air on the left need to be pumped to in order to bring the water and mercury free surfaces level? r tem- ore it 0.85 m Water 3.85 m . 4 m S N. id 2 m Mercury 4 m 3.8 m P3.15, P3.16 3.16 Consider the two-fluid manometer shown. Calculate the applied pressure difference. P1 P2 Water 10.2 mm Carbon tetrachloride P3.16
engineering   Mechanical-Engineering   
0 0
Add a comment Improve this question Transcribed image text
Next > < Previous
Sort answers by oldest

Homework Answers

Answer #1

Asumpions Equok the premot datum ไม่ 82

0 0
Add a comment
Know the answer?
Add Answer to:
Problem 3.16 ;; SG= 1.595 Please clear hind writing 3.15 A partitioned tank as shown contains...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions

  • ((((((please solve it by clear hand write ))))))) The water in a tank is pressurized by...

    ((((((please solve it by clear hand write ))))))) The water in a tank is pressurized by air, and the pressure is measured by a multifluid manometer as shown in Figure Q5. Determine the gage pressure of air in the tank if h,=0.3 m, ha=0.4 m, and hz=0.5 m. Take the densities of water, oil, and mercury to be 1000 kg/m², 850 kg/m?, and 13,600 kg/m², respectively. [16 marks] 1 Water Mercury Figure Q5

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT