Question

In the Figure below, the distance of the point p from the origin at which the electric field equals zero is a) 0.67 m b) 0.73 m c) 1.33 m d) 0.83 m. T Qi=8ục Q2=2 uc 2.00 m 2.00 - x X 92 E=0 9.4

Answer 1

Electric field at P due to q2

E2=Kq2/$x^{2}$

K=electrostatic constant

q2=2$\mu$C

E2=KX2/$x^{2}$

Electric field at P due to q1

E1=Kq1/

(2 - 0)

q1=8$\mu$C

E1=KX8/

(2 - 0)

At P as the total field is zero, E1 cancells E2

Equating E1 and E2

E1=E2

KX8/
(2 - 0)
=KX2/$x^{2}$

4/
(2 - 0)
=1/$x^{2}$

taking square root

2/(2-x)=1/x

2x=2-x

3x=2

x=2/3=.67m

option a