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1. Use golden-section search method with initial guesses of x = 0 and x=3 to minimize the following function: f(x)=10 exp(-x)
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f(4) > flaz) x becomes new a becomes new a xe is same. and Ifecation : xe = 1.146 4 = 1.854 de = 2.291 6 4X=G-R (xu-x) = 0.615th iteration az 1-146 24 = 1.416 Xu z1-583 4x = G-R. Cau-xe) = 0.618 x 0-437 20.27 da = xu - 40 = 1.583 -0.27 = 1.312 2 flas2) Parabolic interpolation : Given x=0 ; x2 = 1 X3 23. eth Ateation: oth I fecation: f(x) = f(0) = 10 0 + 0 = 10 = f(1) = 10efo) 0.433 mo 10 4.67 9.408 0.433 1-584 4.67 9.408 2.696 3 0 .433 1-584 1-786 9 19.408 2-696. 3.066. minimizing the function x

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