Question

A 4-m long, 150-kg steel beam is attached to a wall with one end connected to a hinge that allows the beam to rotate up and down. The other end of the beam is held in a horizontal position with a cable that makes a 27° angle with the beam and is attached

A 4-m long, 150-kg steel beam is attached to a wall with one end connected to a hinge that allows the beam to rotate up and down. The other end of the beam is held in a horizontal position with a cable that makes a 27° angle with the beam and is attached to the wall. A mass of 75 kg is hung from the beam 3 meters away from the hinge (see (Figure 2)). What is the vertical component of the force that the hinge exerts on the beam?


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Answer #1

(mass of steel beam) m = 150kg

(mass of extra thing) M = 75kg

(use the tension found in the previous part) F_t = 2833.2N


net force in y direction = ma

H_y + F_t * sin(27) - M * g - m * g = 0

H_y = 918.75N

source: http://clas.sa.ucsb.edu/staff/vince/physics%202/11.1%20Physics%202%20Static.pdf
answered by: bob man
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A 4-m long, 150-kg steel beam is attached to a wall with one end connected to a hinge that allows the beam to rotate up and down. The other end of the beam is held in a horizontal position with a cable that makes a 27° angle with the beam and is attached
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