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Part A A cruise ship is traveling at a speed of v1 = 23.4 ft/s. A speedboat with a late passenger is heading toward the cruise ship at an angle of 0 = 50.0°; its speed is v2 = 39.4 ft/s. (Figure 1) What is v, the magnitude of the speedboats velocity relative to the cruise ship? Express your answer numerically to three significant figures in feet per second. » View Available Hint(s) V = 26.2 ft/s Submit Previous Answers v Correct Part B As the speedboat approaches the cruise ship, it encounters an ocean current that is moving at v3 = 5.30 ft/s and that is oriented at an angle p = 43.5°. (Figure 2) What are Vs and vy, the scalar components of the speedboats velocity relative to the cruise ship as the speedboat crosses this ocean current? Express your answers numerically to three significant figures in feet per second separated by a comma. » View Available Hint(s) Vz,0y = -29.2,3.13 ft/s Submit Previous Answers v Correct

Part C re=ra+TBA Taking the time derivative of the relative-position equation above results in the following equation that relates the velocities of the particles, Va and VB, with the relative-velocity vector VBA: Figure 3 of 3D After crossing the ocean current, the speedboat continues to approach the cruise ship at 2 = 39.4 ft/s and at an angle = 50.0°. The cruise ship sees the speedboat and slows down by 5 ft/s. At the same time, the speedboat docks with the cruise ship by turning with a radius of curvature of ri = 40.0 ft and by reducing its speed to match that of the cruise ship once it is parallel to the cruise ship. (Figure 3) What are ag and ay, the scalar components of the speedboats acceleration relative to the cruise ships when the speedboat is docked parallel to the cruise ship? Assume that the cruise ships acceleration and the speedboats transverse acceleration are constant. Express your answers to three significant figures in feet per squared second separated by a comma. » View Available Hint(s) Im Azę o vec 6 - O - ? dz, dy = ft/82 Submit

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