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Hath of 0.0078 M at 25°C. What is its pOH? O 9.15 b. 16.11 c.2.11 Od. 4.85 O e 11.89 QUESTION 16 A neon gas sample occupies a
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Answer #1

according to charles law at constant pressure

V1T2 = V2T1

now according to question V1 = 3.62 L T1 = 21.6^c or 294.62K

V2 = 3.45L

to find = T2

therefore (3.62L)(T2) = (3.45L)(294.62K)

therefore T2 = 280.78K or 281K

therefore option D is correct

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