A drug tester claims that a drug cures a rare skin disease 77?% of the time. The claim is checked by testing the drug on 100 patients. If at least 72 patients are? cured, the claim will be accepted.
Find the probability that the claim will be rejected assuming that the? manufacturer's claim is true. Use the normal distribution to approximate the binomial distribution if possible.
here mean number of patients cured =np=100*0.77=77
and std deviaiton =sqrT(np(1-p))=4.2083
hence P( claim will be rejected)=P(less than 72 patients cured)=P(X<72)=P(Z<(71.5-77)/4.2083)
=P(Z<-1.31)=0.0951
A drug tester claims that a drug cures a rare skin disease 77?% of the time....
A drug tester claims that a drug cures a rare skin disease 77% of the time. The claim is checked by testing the drug on 100 patients. If at least 73 patients are cured, the claim l be accepted Find the probability that the claim will be rejected assuming that the manufacturer's claim is true. Use the normal distribution to approximate the binomial distribution if possible. The probability is(Round to four decimal places as needed.)
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please help A certain drug can be used to reduce the acid produced by the body and heal damage to the esophagus due to acid reflux. The manufacturer of the drug claims that more than 92% of patients taking the drug are healed within 8 weeks, in clinical trials, 206 of 221 patients suffering from acid reflux disease were healed after 8 weeks. Test the manufacturer's claim at the a=0 1 level of significance Click here to view the standard...
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