Question

What is oxidized and what is reduced in the following reaction? Find the mass at AICI_3 that is produced when 25.0 grams react with HCl according to the following equation. AL_2o_3 + 6HCL rightarrow 2AlCl_3 + 3H_2)O 32.6 g 159g 72.9g 16.3g 65.4g Any reaction that absorb 150 kcal of energy can be classified as activated reduction oxidation endothermic exothermic How many grams of glucose are needed to prepare 400.mL of a 2.0%(m/v) glucose solution? 8.0g 0.0050g 2.0g 800 g 200g According to LeChatelier's principle, predict whether adding H_2O cause the system to shift in the direction of reactants, products, or no change. NH_4^+(aq) + H_2O(l) reversible NH_3(aq) + H_3o+(aq) products no change reactants A 10.0 mL of 0.121 MH_2SO_4 is neutralized by 17.1 mL of KOH solution. The unbalanced chemical reaction is: H_2SO_4^+ KOH rightarrow K_2SO_4 +H2O Find the molarity of KOH. 0.142 M 0.0708M 0.207M 0.414 M 0.428 M

Answer 1

al What is oxidised and what is reduced in the following reaction

2AI + 3Br2 -------à22A1Br3

What is oxidized and what is reduced in the following reaction? 2Al + 3Br2→ 2AlBr3?

A. Al is oxidized and Br2 is reduced. -answer

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9)

Find the mass of AlCl3 that is produced when 25.0 grams of Al2O3 react with HCl according to the following balanced equation.

Al2O3(s) + 6HCl(aq) → 2AlCl3(aq) + 3H2O(l)

Answer : 65.4 grams

Al2O3(s) + 6 HCl(aq) → 2 AlCl3(aq) + 3 H2O(l)

Assuming that HCl is present in excess and Al2O3 is the limiting reactant,

convert 25.0 grams of Al2O3 to moles of Al2O3,

to moles of AlCl3, to grams of AlCl3.

1 mol Al2O3 = 101.9612 g Al2O3

1 mol Al2O3 = 2 mol AlCl3

1 mol AlCl3 = 133.3405 g AlCl3

[(25.0 g Al2O3)/1][(1 mol Al2O3)/(101.9612 g Al2O3)][(133.3405 g AlCl3)/(1 mol AlCl3)]

= 65.387861 g AlCl3

or

65.4 g AlCl3 --Answer

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