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Problem 1 The machined steel bar shown in the figure undergoes fully reversed axial loading at a nominal alternating stress o
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SOLUTION 6o = 30 ksi Se, corrected = 35 ksi sut 100 ksi syt = 80 ks (i) salety Factor: Se, corrected = (ka-Kbi Кc. Kd) se 2 M16 109/02 B 109,0 sec C 3 103 10 6 [109/10° = 6 10910N. a ABC and A ADE are similae friangles. log log sut seic 10 log, Syt -

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