Question

c++

In the following segment of the code, what will be the output if opening of the file is not successful? ifstream infile; try{ infile.open("test.txt"); if(!infile) throw -1; else cout << "successful" << endl; } catch(const char* msg) { cout << msg << " unsuccessful" << endl; } catch(int i) { cout << i < was returned, unsuccessful" <<endl; #8 WA w

Answer 1

OUTPUT:

-1 was returned, unsuccessful

If there is an error in reading the file "text.txt", then the condition 'if(!infile)' will become true, and the statement 'throw -1' will get executed.

The throw statements directs the program control to the catch block. Now, we have 2 catch blocks which can be executed. Since the throw statement send an integer(-1) to the catch block, hence the second catch block, which accepts an integer parameter will get executed.

The catch block executed will be:

catch(int i){

cout<< i << " was returned, unsuccessful" << endl;

}

'int i' will have the value of '-1' passed to it by the throw statement.

Hence the final output will be:

-1 was returned, unsuccessful