Question

- What is the molarity of a solution in which 0.051 grams of sodium thiosulfate is prepared in a solution having a total volume of 200.00 mL Neutralization is the reaction between an acid and a base, producing a salt and neutralized base. For example, hydrochloric acid and sodium hydroxide form sodium chloride and water: HCl(aq)+ NaOH(aq) H2O0+NaCl(aq) a. Using the previous reaction, if 35 ml of 0.1 M NaOH will neutralize 10 mL of HCl, what is the concentration of the acid. b. Using the molarity in Part A, how many mL of 12 M HCL would be need to prepare 15 liters of the molarity in part A..

Answer 1

Molar Mess of Sodium thubsulfate & X23+ 32x2 † 16x3 (ara, $23) : 158gfunt Criven men of Soclum thosulfate = 0.051 gram Noso 23 ? 22 liven Mess Molar miss = 0.0519 - 158 g/mol = 3.23x10 mol Mobrity = of Nqs no of moles of Ny los volume of solution in me -- tioco s 3:23 1109 So 200 : : 1.67 X103 M

a Hellas) + Naon Car) hole) twach (as) The net imic equetion of what really react i Ht tou no Neutralization occurs when the no. Smoles of ut no. of moles of on from acid - from bere (Molarity & volume) acid (Molarity xvolume bare MA % , , , , Ma x 10mil : 35mc x 0.1M Mq: 35 Xolm [Ma=0.35M), so, molarity of ne= 0.35m

6 for dilution M, Via M₂ . 12 M X V, - 0,35 M X 15 L via 0.35415 L 0.4375L - 437.5 mL soy : 437.5 mL of 12m her needed to prepared is of 0.35MHY.