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This Question: 14 pts 18 of 24 (16 complete) This Quiz: 250 pts pos In a survey of 3034 adults, 1429 say they have started paying bills online in the last year Construct a 99% confidence interval for the population proportion Interpret the results A 99% confidence interval for the population proportion is (LLD (Round to three decimal places as needed.) Interpret your results. Choose the correct answer below. 0 A. The endpoints of the given confidence interval show that adults pay bills online 99% of the time. О в eendpoi is of heg en confidence ne vai with 99% confidence with 99% co n dence, t can be said that the po can be said that he sample proportion of a uns who say 속 have s ar e pa ng bis on ne n the as ars between c. uation proportion of adults who sa h y have sar Day ng b son ne n h las eat s etween heen onts a heger! on de cent

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Answer #1

sample size sample proportion 1429 3034.0 0.4710 p x/n std error Se p*(1-p)/n) = 0.0091 for 99 % Cl value of z= margin of error E-z*std error lower confidence bound-sample proportion-margin of error Upper confidence bound-sample proportion+margin of error 2.576 0.023 0.448 0.494

99% confidence interval =0.448 ; 0.494 ( please try 0.448 ; 0.495 if this comes wrong)

option C is correct

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