The magnetic field at the centre of a solenoid of length 0. 25 m is 1....
A solenoid 5 cm in diameter and 30 cm in length has 4000 turns and carries a current of 5 A. Calculate the magnetic flux through the circular cross-sectional area of the solenoid. Since this is a very long solenoid, you may use the simplified magnetic field formula for the infinite solenoid
The magnetic field of a long thin solenoid is approximately zero outside the solenoid and a uniform Bsol inside the solenoid. A square conducting frame is located as shown. The large frame is located entirely outside the solenoid while the small frame is located entirely inside the solenoid. The frame and solenoid are oriented so their axis coincide. What is the magnetic flux through the square frame? A. Bsol times the area of the frame for the top case and...
A solenoid 2.5 cm in diameter and 30 cm in length has 5000 turns and carries a current of 2.0 A. Calculate the magnetic flux through the circular cross-sectional area of the solenoid. Hint: Assume this is a very long solenoid and use the simplified magnetic field formula for an infinite solenoid.
SERCP8 20.P.006. A 410 turn solenoid of length 33.0 cm and radius 2.90 cm carries a current of 4.90 A. Find the following. (a) the magnetic field strength inside the coil at its midpoint MT (b) the magnetic flux through a circular cross-sectional area of the solenoid at its midpoint To m² Need Help? Read It Talk to a Tutor
3. (20 points) A solenoid has a length of 0.1 m and cross sectional area 104 m2 The total number of turns of wire isN-1000. The current in the wire is 1-0.01 sin (100 π t). μο 4TY 107 in our SI units, a) Find the magnetic field B(t) inside the solenoid. b) Find the magnetic flux Ф, (t) inside the solenoid. c) Express the induced voltage on one turn of the wire,in terms of dI/dt. What is the inductance...
3 The magnetic field inside a toroidal solenoid is not uniform as for the long, straight solenoid. Over the cross-sectional area of the toroid the magnetic field is stronger near the inner HoNI radius of the torus and somewhat weaker near the outer radius according to B(r) 2Tr So we cannot technically use the simple expression P2 = BAfor the flux through one turn of wire. Nevertheless, the textbook uses an approximate constant value for an equivalent uniform magnetic field...
Problem 5: The magnetic field strength in a long superconducting solenoid buried underground in Switzerland is 15:0 T. The cross sectional area of the solenoid is 3.0x10^-4 m^2 ; and its length is approximately 40 km. If a loss of cooling allows the superconducting wires to suddenly become normal, so that B drops to zero, how much energy will be released as heat?
The solenoid shown below has length l = 0.15 m and cross-sectional area A = 3.5 × 10-4 m2. Its self-inductance is L = 25 mH. A current I of 2.5 amps flows through its coils in the direction shown in the figure. 2. How much magnetic energy, Um, is stored in this solenoid? 3.What is the magnetic field inside the solenoid. (a) B = 14 mT (b) B = 36 mT (c) B = 48 mT (d) B = 61 mT (e) B =...
Ch.2 Problem 21.42 31 of 32> Part A Constants Calculate the magnetic field in the solenoid A solenoid 29.0 cm long and with a cross-sectional area of 0.570 cm2 contains 400 turns of wire and carries a current of 70.0 A Submit Request Answer Part B Calculate the energy density in the magnetic field if the solenoid is filled with air. J/m
A solenoid has a length of 25 cm, a diameter of 2.4 cm and 400 turns. The solenoid carries a current of 3 A. Calculate: A. The magnetic field on the axis at the center of the solenoid. (5 pts) B. The magnetic flux through the solenoid assuming the magnetic field is uniform. (5 pts) C. The self-inductance of the solenoid. (5 pts) D. The magnetic energy stored in the solenoid if the current is increased to 4 A. (5...