a stone dropped down a well at t =0 seconds and a splash is heard 3.9 seconds later. how deep is the well use Ad^2+Bd+C=0 then d=-+-B(B^2-4AC)^(1/2)/2A
a stone dropped down a well at t =0 seconds and a splash is heard 3.9...
A stone is dropped from rest into a well. The sound of the splash is heard exactly 3.90 s later. Find the depth of the well if the air temperature is 16.0°C.
A stone is dropped from rest into a well. The sound of the splash is heard exactly 1.90 s later. Find the depth of the well if the air temperature is 8.0°C
A stone is dropped from rest into a well. The sound of the splash is heard exactly 3.40 s later. Find the depth of the well if the air temperature is 15.0°C. m
A stone is dropped from rest into a well. The sound of the splash is heard exactly 2.30 s later. Find the depth of the well if the air temperature is 6.0°C. m
A stone is dropped into a well. The sound of the splash is heard 4.80 s later. What is the depth of the well? (Take the speed of sound to be 343 m/s.)
A stone is dropped into a well. The sound of the splash is heard 4.15 s later. What is the depth of the well? (Take the speed of sound to be 343 m/s.)
A stone is dropped from rest into a well. The sound of the splash is heard exactly 4.00 s later. Find the depth of the well if the air temperature is 16.0°C. m
A stone is dropped from the top of a cliff. The splash it makes when striking the water below is heard 4.1s later. The speed of sound in air is 343 m/s. How high is the cliff?
A stone is dropped from the top of a cliff. The splash it makes when striking the water below is heard 3.5 s later. The speed of sound in air is 343 m/s. How high is the cliff? Express your answer to two significant figures and include the appropriate units.
A stone is dropped into a deep well and sound of hitting is heard after 8.62 sec. Sound velocity is 335 m/s. Find the depth of the well. Assume g=10 m/s [attention - in this problem, maintain 8 digits after decimal point instead of 4 which you always do]