Question

The U.S. Department of Transportation, National Highway Traffic Safety Administration, reported that 77% of all fatally injured automobile drivers were intoxicated. A random sample of 28 records of automobile driver fatalities in Kit Carson County, Colorado, showed that 14 involved an intoxicated driver. Do these data indicate that the population proportion of driver fatalities related to alcohol is less than 77% in Kit Carson County? Use α = 0.01. Solve the problem using both the traditional method and the P-value method. Since the sampling distribution of p̂ is the normal distribution, you can use critical values from the standard normal distribution as shown in the table of critical values of the z distribution. (Round the test statistic and the critical value to two decimal places. Round the P-value to four decimal places.)

test statistic =

critical value =

P-value =

USA Today reported that about 47% of the general consumer population in the United States is loyal to the automobile manufacturer of their choice. Suppose Chevrolet did a study of a random sample of 1008 Chevrolet owners and found that 490 said they would buy another Chevrolet. Does this indicate that the population proportion of consumers loyal to Chevrolet is more than 47%? Use α = 0.01.

(a) What is the level of significance?

  

thumps up to anyone that helps thank you (:

10. 0.41 points | Previous Answers BBUnderStat12 8.3.023. My Notes Ask Your Teacher The U.S. Department of Transportation, National Highway Traffic Safety Administration, reported that 77% of all fatally injured automobile drivers were intoxicated. A random sample of 28 records of automobile driver fatalities in Kit Carson County, Colorado, showed that 14 involved an intoxicated driver. Do these data indicate that the population proportion of driver fatalities related to alcohol is less than 77% in Kit Carson County? Use a = 0.01. Solve the problem using both the traditional method and the P- value method. Since the sampling distribution of p is the normal distribution, you can use critical values from the standard normal distribution as shown in the table of critical values of the z distribution. (Round the test statistic and the critical value to two decimal places. Round the P-value to four decimal places.) test statistics critical value = P-value

Answer 1

Sokitioni- the UC Chportmous of toorks parklion inbrione high comes Required information is given by X=14 9:28 P: 44%. + 100 (p=0.17] -> Population proportion is, Calculate @ Find the test (statistic:- pypothesis and test Statistic value is cwe have to obtained the Esere - Hypothesis is null bypothe Git is Ho: P= 03} and Alternative hypothesis (HA: P20.4+] -> Meest (statistic Kalcie is z = Lop PCI-D] PCI-PT

7. 60.5-0.11) [.100.10) No No 03] V 08 -0.01 11-10 ✓ OB 2 395-4103 2: -0.91 0.0795 [7--0.894] 7 = - 3.89 Therefore test (statistic = (-3.39 © Find the Critical calculis hale to obtained the Critical Value bg asing giver data Here zcritical = ZEW = 710.01) 1Zcritical = -2.3263 J Z-fest and E-critical Calcio - we have to compared the Eere . Z test -3.39 a z-critical 3-2.3263

Rajechas the roll bagno, llacsicalW10.01) Oring - 17.00 at halo to obhind the pucalis by using given dala is pvalu = 67-best) = (-3.39) (pralna 0.000551 - we hace to Compored the place and a=ool ! Eers pallalis & 0.00035 0.01 Rejected the sun bypothesi's Ho, al(Q=0.01) r -Finally conclude that given decision is the fera coe Can not Conclude that the population proportion of drikker falailites related to alochal is less than 371. in kit Carson County:

Lol of the generale about lofth coepol that Abozcuired information ilgilen by X: (190 D 1008 p=4+1 100 [p = 0.47] - Population = proportions - 400 1008 P = 0.61861) 2=0.01 Calculate a. cohat is the love of signi# Corse significance is, he hale to the level of oblained Clere level signifione is 25001] @obat is the value of test stahistic test Statistic by casing We have to obtained the gillen data is felst Statistic is. pli-p

0.41861 - 0:41] 7 1006 0.0161 O YO.53 1008 clo o. CY 1008 V 2. 006) 9.091230-10-4 0.016! 015120 Z1.0941 =1021 Therefore Komple test Caristic ios 11-02 value © Find - We have to obtained places by using give tee is prala is, pvalue= CZ * = [1.00] = 0.15385 produe= 0.1539] Therefore, pralce is 0- 1539)

- we have to compared the p alua and aro.01 in Cere, p Kalwe >a 0.0503855 0.01 Failed to crejected the sall hypothesis, at a rool There show fore, G à insufficient evidence to Sided to rejected Ho.