Two identical cars (m = 1350 kg) are traveling at the same speed
of 31.5 m/s. They are moving in the directions shown in the
drawing. What is the magnitude of the total momentum of the two
cars?
Magnitude of total momentum = kg
let x axis be unit vector i and y-axis be unit vector j.
then speed of left side mass=-sin(60) i+cos(60) j
=-0.866 i+0.5 j
velocity of second mass=sin(30) i+ cos(30) j=0.5 i+0.866 j
so net momentum=1350*31.5*(-0.866 i+0.5 j)+1350*31.5*(0.5 i+0.866 j)=-15564.15 i +58089.15 j
Two identical cars (m = 1350 kg) are traveling at the same speed of 31.5 m/s....
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