Question

8. Use the method of slack variables, along with the pivot() function given on iLearn (and demonstrated in lecture), to find the maximum of the objective function /(*1,02) = 21 +382 subject to the following constraints: 0+32 > 2, (1a) +262 36, (16) -31 +32 51, (1c) 31,39 0. (10) Because there are three constraints (not counting the two non-negativity constraints), there should be throe slack variables. Use the pivot() function to find the four vertices of the feasible region. Hence, find the maximum of (11,12) subject to the above constraints. Submit the following: A MATLAB-generated plot that contains the following: the bounding lines corresponding to constraints (la)-(1e) (use the grid on command to display a grid); • labeled coordinates of the four vertices of the feasible region; one easy way to do this is to click "Insert" at the top of the figure window to the right of "File" and "Edit") and then click "TextBox." Then click and drag on the figure to make the text box; its location and size can be adjusted as desired • a title indicating the value and the location of the maximum of f(*1, 12) subject to the above constraints; it should be of the form 'max of / is p; occurs at (a,b)'. The plot should have dı as the horizontal axis, 19 as the vertical axis, and be plotted over the region * € (0,6 and 12 € (0,6). Hand-drawn plots will not receive credit.

Answer 1

Answer is -

The maximum of given function is 8 by (2,2) vertics of feasible solution

Page No.- 7,82 70 then Ang. Given f(n1, 12) = = nit 312 Hit 127, 2 Hit 24256 -Yi+372 34 n, 127,0 Using method of slack Variables f(y X2) = ni+32 -21-12-2 717242 36 -nit 312 54 'f(n,na- ,112 ----M5) = --H) = n1+ 3N2 + 0 13+ only tons -X-712 +13 261 +232 try 6 4 -211 +302 11, 22, 23, dly, ns 7.0 4) B XB ь 13 -2 6 2 4/M4 3 43 → 1 (256) 1 (departing (Entering vector) Vector) Here L2 is entering Vector & as is departing Vectori elemento CS Scanned of 3 is key CamScanner try 0 3 o y5 min. Roolio 0 -1 - 0- 6 -1 1x5ns 4 0 0