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Instructor HW7 Ch. 26 Electric Potential & EPE You must show all work to receive max credit y(m 3. A charge q+2* 10 C is loca
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Answer #1

Part A

Electric potential is defined as

ke

for 1 and g2

ke 9 x 109 Nm2 C2

r 2m 1m) (-2m 2m 5 m (distance from q to P)

T (1m 3m) (2m 1m) = 2.24 m (distance from q to P)

substituting

-5 x 10 2 x 10 V12 (9 x 10) =-1.65 x 106 V 2.24

Electric\:field\:is\:generated\:radially\:at\:any\:position.

Part B

CHange\:in\:potential\:energy\:is\:defined\:as:

\Delta U=U_f-U_i

U_i=0

Uf=3V12

U_f=\left ( 4\times 10^{-4}\:C \right )\left ( -1.65\times 10^{6}\:V \right )=-660\:J

The work done is

W=F_ed

for\:q_1:

W_{13}=\left ( k_e\frac{\left | q_1 \right |\left | q_3 \right |}{r_{1}^{2}} \right )r_1=\left ( 9\times 10^{9} \right )\left ( \frac{\left ( 2\times 10^{-4} \right )\left ( 4\times 10^{4} \right )}{5} \right )=144\:J

W_{23}=\left ( k_e\frac{\left | q_2 \right |\left | q_3 \right |}{r_{2}^{2}} \right )r_2=\left ( 9\times 10^{9} \right )\left ( \frac{\left ( 5\times 10^{-4} \right )\left ( 4\times 10^{-4} \right )}{2.24} \right )=803.57\:J

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