A 37.80 mH coil carries a constant current of 2.80 A, clockwise. If the current drops...
A 37.80 mH coil carries a constant current of 2.80 A, clockwise. If the current drops to zero and rises in the opposite direction (conterclockwise) to 0.15 A in 93.00 microseconds, what potential difference will appear across the coil during this time?
Homework Answers
Potential difference V = LdI/ dt
L = 37.8 mH= 0.0378 H, dI = (2.8) - (-0.15) = 2.95 A , dt = 93ms = 0.093 s
Hence, V = 0.0378 X 2.95 / 0.093 = 1.20 V
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