Question

need help

1. Two BLOCKS AND A SPRING am Consider the diagram above. Both blocks have mam . The spring constant is k. The coefficients of static and kinetic friction are p, and respectively. Initially the system is at rest and the spring is not stretched to do this the bottom ma that is hanging off of the table is held). Then the bottom mass is released A) How far does the spring stretch before the bottom mass stops moving? B) What is the minimum value of us in order for the system to remain in equi- librium afterwords? That is once the bottom mass descends to it's lowest position, the static friction on the first block should prevent the system from moving

Answer 1

[f= MxR , R = mg] granitational potential energy = energy of spring & wark done by frietion. та - кә* + та . 1 like = mg - uk ng x= [2 mg (1-Uk) the spring will streten n = | 2 mg (1- Uk) and the Now once it get streatched mass mg will oppage the the spring static friction force. : I F=-kx qR coopements F= fst mg. kr = lg ing + mg. :. Mc-ka-ng mg